Created
March 16, 2021 15:46
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Fractal tree: a solution for a beautiful task from HackerRank (https://www.hackerrank.com/challenges/fractal-trees-all/problem)
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# same implemented in python as a POC | |
N=5 | |
print('_' * 100) | |
offset = 0 | |
for i in range(5-N): | |
offset += 2 ** i | |
for j in range(2 ** i * 2): | |
print('_' * 100) | |
for i in range(6-N, 6): | |
points=2 ** (i - 1) | |
cnt = 2 ** (5 - i) | |
spc = 2 ** i - 1 | |
for j in range(points): | |
print('_' * 18, end='') | |
for k in range(cnt): | |
print('_' * offset, end='') | |
print('1' + ('_' * spc) + '1', end='') | |
print('_' * offset, end='') | |
print('_', end='') | |
print('_' * 18) | |
offset += 1 | |
spc -= 2 | |
for j in range(points): | |
print('_' * 18, end='') | |
for k in range(cnt): | |
print('_' * offset, end='') | |
print('1', end='') | |
print('_' * (offset + 1), end='') | |
print('_' * 18) |
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#! /bin/bash | |
read N | |
# N=4 | |
printf '_%.0s' {1..100} | |
echo | |
offset=0 | |
for ((i=0; i<5-N; i++)); do | |
offset=$((offset + 2 ** i)) | |
for ((j=0; j<2 ** i * 2; j++)); do | |
printf '_%.0s' {1..100} | |
echo | |
done | |
done | |
for ((i=6-N; i<6; i++)); do | |
points=$((2 ** (i - 1))) | |
cnt=$((2 ** (5-i))) | |
spc=$((2 ** i - 1)) | |
for ((j=0; j<points; j++)); do | |
# printf '%2d, %2d, %2d' $points $cnt $j | |
printf '_%.0s' {1..18} | |
for ((k=0; k<cnt; k++)); do | |
if [[ $offset -gt 0 ]]; then | |
printf '_%.0s' $(seq 1 $offset) | |
fi | |
printf '1' | |
printf '_%.0s' $(seq 1 $spc) | |
printf '1' | |
if [[ $offset -gt 0 ]]; then | |
printf '_%.0s' $(seq 1 $offset) | |
fi | |
printf '_' | |
done | |
printf '_%.0s' {1..18} | |
echo | |
offset=$((offset + 1)) | |
spc=$((spc - 2)) | |
done | |
for ((j=0; j<points; j++)); do | |
printf '_%.0s' {1..18} | |
for ((k=0; k<cnt; k++)); do | |
printf '_%.0s' $(seq 1 $offset) | |
printf '1' | |
printf '_%.0s' $(seq 1 $offset) | |
printf '_' | |
done | |
printf '_%.0s' {1..18} | |
echo | |
done | |
done |
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