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@dmitriy-kiriyenko
Created November 28, 2017 10:00
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1.3

Ruby

def f(a, b, c)
  a < b && a < c ? b*b + c*c : f(b, c, a)
end

JS

function f(a, b, c) {
  return a < b && a < c ? b*b + c*c : f(b, c, a)
}
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