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Largest Palindrome Product of Two Three Digit Numbers
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//Brute Force | |
public class LargestPalindrome | |
{ | |
public static void main(String[] args) | |
{ | |
MaxPalindrome myObject = new MaxPalindrome(); | |
int maxPal = myObject.findLargestPalindromeThreeDigits(); | |
System.out.println(String.format("Max Product: %-4d", maxPal)); | |
} | |
} | |
public class MaxPalindrome | |
{ | |
public int findLargestPalindromeThreeDigits(){ | |
int max = 0; | |
for (int i = 999; i > 800; i--){ | |
for (int j = i; j > 800; j--){ | |
int prod = i * j; | |
if (isPalindrome(prod) && prod > max){ | |
System.out.println(String.format("palindrome: %-4d, product of %-4d and %-4d", prod, i, j)); | |
max = prod; | |
} | |
} | |
} | |
return max; | |
} | |
public boolean isPalindrome(int product){ | |
String prod = Integer.toString(product); | |
if (prod.equals(new StringBuilder(prod).reverse().toString())){ | |
return true; | |
} | |
return false; | |
} | |
} | |
/*output: | |
palindrome: 906609, product of 993 and 913 | |
Max Product: 906609 | |
*/ | |
//Using Math | |
//http://stackoverflow.com/questions/7183977/find-the-largest-palindrome-made-from-the-product-of-two-3-digit-numbers | |
public class LargestPalindrome | |
{ | |
public static void main(String[] args){ | |
parent: | |
for(int i=9; i>0;i--){ | |
for(int j=9; j>=0; j--){ | |
for(int k=9; k>=0; k--){ | |
int palindrome = i*100001+j*10010+k*1100; | |
int temp = (palindrome-(palindrome%1000))/1000+1; | |
for(int m = temp; m<Math.sqrt(palindrome);m++){ | |
if(palindrome%m==0){ | |
System.out.println("The biggest number is: "+palindrome); | |
System.out.println(palindrome+" = "+m+"*"+palindrome/m); | |
break parent; | |
} | |
} | |
} | |
} | |
} | |
} | |
} | |
/*output | |
The biggest number is: 906609 | |
906609 = 913*993 | |
*/ |
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