Bartender initial solution (Gerard)

bartender.py

# yes = True
# y = True
# no = False
# n = False

questions = {
    "strong": "Do ye like yer drinks strong?",
    "salty": "Do ye like it with a salty tang?",
    "bitter": "Are ye a lubber who likes it bitter?",
    "sweet": "Would ye like a bit of sweetness with yer poison?",
    "fruity": "Are ye one for a fruity finish?",
}


Preferences = {}

ingredients = {
    "strong": ["glug of rum", "slug of whisky", "splash of gin"],
    "salty": ["olive on a stick", "salt-dusted rim", "rasher of bacon"],
    "bitter": ["shake of bitters", "splash of tonic", "twist of lemon peel"],
    "sweet": ["sugar cube", "spoonful of honey", "spash of cola"],
    "fruity": ["slice of orange", "dash of cassis", "cherry on top"],
}

def Bartender (yes,y,no,n):
    """You tell me what you like, I make it!"""
    print("I'm a function. My name is {}".format(Bartender.__name__))
    print("I'm a bit slow, I only accept yes or no answers")
    print("{}". format(questions['strong']))
    input("answer")
    if "answer" == True:
        Preferences['strong'] = 1
    print("{}". format(questions['salty']))
    input ("")
    print("{}". format(questions['bitter']))
    input ("")
    print("{}". format(questions['sweet']))
    input ("")
    print("{}". format(questions['fruity']))
    input ("")

   
    
if __name__ == '__main__':
    Bartender (yes,y,no,n)

    print("{}". format(questions['salty']))
    input ("")
    print("{}". format(questions['bitter']))
    input ("")
    print("{}". format(questions['sweet']))
    input ("")
    print("{}". format(questions['fruity']))
    input ("")

Do you really need to look up each question separately? Can' you loop through the dictionary items and ask the question instead?

Partial code:

for `each question in questions`:
    print(question)

You just need to figure out how to loop through the items in a dictionary.

def Bartender (yes,y,no,n)

Again it is not idiomatic Python to start variable, function, class, method names etc to start with upper case.

def bartender(yes, y, no, n is much better.

if "answer" == True:
        Preferences['strong'] = 1

• Won't the user enter yes, y, no, n for an answer, IIRC. Then you should be comparing answering with that.
• Also, you can store Booleans in a dictionary. So that makes it evident that preferences['strong'] = 1 has a simpler solution.