source: Start Small: Calulating sunrise and sunset in Python https://michelanders.blogspot.com/2010/12/calulating-sunrise-and-sunset-in-python.html

sunset.py

from math import cos,sin,acos,asin,tan  
from math import degrees as deg, radians as rad  
from datetime import date,datetime,time  
  
# this module is not provided here. See text.  
from timezone import LocalTimezone  
  
class sun:  
 """  
 Calculate sunrise and sunset based on equations from NOAA 
 http://www.srrb.noaa.gov/highlights/sunrise/calcdetails.html 
 
 typical use, calculating the sunrise at the present day: 
  
 import datetime 
 import sunrise 
 s = sun(lat=49,long=3) 
 print('sunrise at ',s.sunrise(when=datetime.datetime.now()) 
 """  
 def __init__(self,lat=52.37,long=4.90): # default Amsterdam  
  self.lat=lat  
  self.long=long  
    
 def sunrise(self,when=None):  
  """ 
  return the time of sunrise as a datetime.time object 
  when is a datetime.datetime object. If none is given 
  a local time zone is assumed (including daylight saving 
  if present) 
  """  
  if when is None : when = datetime.now(tz=LocalTimezone())  
  self.__preptime(when)  
  self.__calc()  
  return sun.__timefromdecimalday(self.sunrise_t)  
    
 def sunset(self,when=None):  
  if when is None : when = datetime.now(tz=LocalTimezone())  
  self.__preptime(when)  
  self.__calc()  
  return sun.__timefromdecimalday(self.sunset_t)  
    
 def solarnoon(self,when=None):  
  if when is None : when = datetime.now(tz=LocalTimezone())  
  self.__preptime(when)  
  self.__calc()  
  return sun.__timefromdecimalday(self.solarnoon_t)  
   
 @staticmethod  
 def __timefromdecimalday(day):  
  """ 
  returns a datetime.time object. 
   
  day is a decimal day between 0.0 and 1.0, e.g. noon = 0.5 
  """  
  hours  = 24.0*day  
  h      = int(hours)  
  minutes= (hours-h)*60  
  m      = int(minutes)  
  seconds= (minutes-m)*60  
  s      = int(seconds)  
  return time(hour=h,minute=m,second=s)  
  
 def __preptime(self,when):  
  """ 
  Extract information in a suitable format from when,  
  a datetime.datetime object. 
  """  
  # datetime days are numbered in the Gregorian calendar  
  # while the calculations from NOAA are distibuted as  
  # OpenOffice spreadsheets with days numbered from  
  # 1/1/1900. The difference are those numbers taken for   
  # 18/12/2010  
  self.day = when.toordinal()-(734124-40529)  
  t=when.time()  
  self.time= (t.hour + t.minute/60.0 + t.second/3600.0)/24.0  
    
  self.timezone=0  
  offset=when.utcoffset()  
  if not offset is None:  
   self.timezone=offset.seconds/3600.0  
    
 def __calc(self):  
  """ 
  Perform the actual calculations for sunrise, sunset and 
  a number of related quantities. 
   
  The results are stored in the instance variables 
  sunrise_t, sunset_t and solarnoon_t 
  """  
  timezone = self.timezone # in hours, east is positive  
  longitude= self.long     # in decimal degrees, east is positive  
  latitude = self.lat      # in decimal degrees, north is positive  
  
  time  = self.time # percentage past midnight, i.e. noon  is 0.5  
  day      = self.day     # daynumber 1=1/1/1900  
   
  Jday     =day+2415018.5+time-timezone/24 # Julian day  
  Jcent    =(Jday-2451545)/36525    # Julian century  
  
  Manom    = 357.52911+Jcent*(35999.05029-0.0001537*Jcent)  
  Mlong    = 280.46646+Jcent*(36000.76983+Jcent*0.0003032)%360  
  Eccent   = 0.016708634-Jcent*(0.000042037+0.0001537*Jcent)  
  Mobliq   = 23+(26+((21.448-Jcent*(46.815+Jcent*(0.00059-Jcent*0.001813))))/60)/60  
  obliq    = Mobliq+0.00256*cos(rad(125.04-1934.136*Jcent))  
  vary     = tan(rad(obliq/2))*tan(rad(obliq/2))  
  Seqcent  = sin(rad(Manom))*(1.914602-Jcent*(0.004817+0.000014*Jcent))+sin(rad(2*Manom))*(0.019993-0.000101*Jcent)+sin(rad(3*Manom))*0.000289  
  Struelong= Mlong+Seqcent  
  Sapplong = Struelong-0.00569-0.00478*sin(rad(125.04-1934.136*Jcent))  
  declination = deg(asin(sin(rad(obliq))*sin(rad(Sapplong))))  
    
  eqtime   = 4*deg(vary*sin(2*rad(Mlong))-2*Eccent*sin(rad(Manom))+4*Eccent*vary*sin(rad(Manom))*cos(2*rad(Mlong))-0.5*vary*vary*sin(4*rad(Mlong))-1.25*Eccent*Eccent*sin(2*rad(Manom)))  
  
  hourangle= deg(acos(cos(rad(90.833))/(cos(rad(latitude))*cos(rad(declination)))-tan(rad(latitude))*tan(rad(declination))))  
  
  self.solarnoon_t=(720-4*longitude-eqtime+timezone*60)/1440  
  self.sunrise_t  =self.solarnoon_t-hourangle*4/1440  
  self.sunset_t   =self.solarnoon_t+hourangle*4/1440  
  
if __name__ == "__main__":  
 s=sun(lat=52.37,long=4.90)  
 print(datetime.today())  
 print(s.sunrise(),s.solarnoon(),s.sunset())  

original source was this, maybe? Start Small: Calulating sunrise and sunset in Python

original source was this, maybe? Start Small: Calulating sunrise and sunset in Python

I think you're correct, thanks for pointing it out!