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July 26, 2022 10:43
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Adds @danielafcarey fix
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from django import template | |
register = template.Library() | |
@register.filter | |
def cool_number(value, num_decimals=2): | |
""" | |
Django template filter to convert regular numbers to a | |
cool format (ie: 2K, 434.4K, 33M...) | |
:param value: number | |
:param num_decimals: Number of decimal digits | |
""" | |
int_value = int(value) | |
formatted_number = '{{:.{}f}}'.format(num_decimals) | |
if int_value < 1000: | |
return str(int_value) | |
elif int_value < 1000000: | |
return formatted_number.format(int_value/1000.0).rstrip('0').rstrip('.') + 'K' | |
else: | |
return formatted_number.format(int_value/1000000.0).rstrip('0').rstrip('.') + 'M' |
@dnmellen Thank you for this awesome piece!
@danielafcarey Thank you for the correction, it was really helpful!
Please how do I use it in my template? Thanks
@danielafcarey Thanks for your correction!
@dantechplc Checkout Django's docs about custom filters (https://docs.djangoproject.com/en/3.2/howto/custom-template-tags/). You need to add this file inside templatetags
folder within your django app directory as it says in the docs. After that you can load that custom filter in your template and use it:
{% load numbers %}
...
{{ yourvar|cool_number }}
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This is great - thank you! One small note is that it doesn't work for numbers like 40000 because the
rstrip('0.')
strips all the combinations of the passed in char string so it would result in40.0
being stripped down to4
and output4k
when it should be40k
A workaround I found was to replace
rstrip('0.')
withrstrip('0').rstrip('.')
which will remove all trailing zeros and then any trailing decimals.