Separate street & housnumber

address_separator.py

def separate_street_and_number(address):
    '''
    Split by " " and check for the index of the first element that STARTSWITH a number.
    Everything before that index is the street name, so " ".join()
    Everything after is the house number.

    # K1 | 1-4
    # E1 | 15
    # Bahnhofstr. | 27
    # Marienbrunnen | 10 a
    # Bunte Allee | 2 a-c
    # Goethestr | 7a

    https://gist.github.com/do-me/c2a6fdf29a7ee3837cf94a57920cad4b
    '''

    # Split the address by spaces
    parts = address.split(" ")

    # Find the index of the first element that STARTSWITH a number
    index = next((i for i, part in enumerate(parts) if part and part[0].isdigit()), None)

    if index is not None:
        # Everything before the index is the street name
        street_name = " ".join(parts[:index])

        # Everything after the index is the house number
        house_number = " ".join(parts[index:]) if index < len(parts) else None

        return street_name, house_number
    else:
        # No valid house number found, return the entire address as the street name
        return address, None

Logic from me, (slightly modified) code from ChatGPT with this prompt:

I need an efficient python function that separates streetname from housenumber (and additions).
These are examples

K1 1-4
E1 15
Bahnhofstr. 27
Marienbrunnen 10 a
Bunte Allee 2 a-c

Implement this logic:

1. Split by " " and check for the index of the first element where only numbers and minues occur so that entries like "10" or "2-4" are both valid but "E7" is not.
2. Everything before that index is the street name, so " ".join()
3. Everything after is the housenumber