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September 28, 2020 13:03
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C implementation of algorithm 2.1 and 2.2 from *The Nurbs Book*
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#include <stdio.h> | |
#include <stdlib.h> | |
int findSpan( int n, int p, double u, double U[]) { | |
if (u == U[n+1]) return(n); | |
int pos = n/2; | |
int step = (pos < 4) ? 1 : pos / 2; | |
while (u < U[pos] || u >= U[pos+1]) { | |
pos += step * (( u >= U[pos]) * 2 - 1); | |
step = (step + 1)/2; | |
} | |
return pos; | |
} | |
void baseFuncs( int i, double u, int p, double U[], double N[]) { | |
double left[p+1]; | |
double right[p+1]; | |
N[0]=1.0; | |
for (int j=1; j<=p; ++j) { | |
left[j] = u - U[i+1-j]; | |
right[j] = U[i+j] - u; | |
double saved = 0.0; | |
for (int r=0; r<j; ++r) { | |
double temp= N[r]/(right[r+1]+left[j-r]); | |
N[r] = saved+right[r+1]*temp; | |
saved = left[j-r]*temp; | |
} | |
N[j] = saved; | |
} | |
} | |
int main() { | |
double U[] = {0, 0, 0.2, 0.3, 0.6, 0.9, 1, 1}; | |
const int p = 2; | |
const int sU = sizeof U / sizeof U[0]; | |
const int n = sU - p - 1; | |
double N[p+1]; | |
// FILE * outf = stdout; | |
FILE * outf = fopen("base.txt","w"); | |
for ( double u = 0; u < 1; u += 1e-3 ) { | |
fprintf ( outf, "%.6f", u ); | |
int i = findSpan(n,p,u,U); | |
baseFuncs( i, u, p, U, N); | |
for (int x = p-1; x < i; ++x) fprintf ( outf, " %.3f", 0. ); | |
for (int x = 0; x < p+1; ++x) fprintf ( outf, " %.3f", N[x] ); | |
for (int x = i + p + 1; x < sU; ++x) fprintf ( outf, " %.3f", 0. ); | |
fprintf ( outf, "\n" ); | |
} | |
if (outf && outf != stdout) fclose(outf); | |
return 0; | |
} |
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