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@dtaivpp
Created January 9, 2020 14:29
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# Courtesy of https://stackabuse.com/sorting-algorithms-in-python/
def heapify(nums, heap_size, root_index):
# Assume the index of the largest element is the root index
largest = root_index
left_child = (2 * root_index) + 1
right_child = (2 * root_index) + 2
# If the left child of the root is a valid index, and the element is greater
# than the current largest element, then update the largest element
if left_child < heap_size and nums[left_child] > nums[largest]:
largest = left_child
# Do the same for the right child of the root
if right_child < heap_size and nums[right_child] > nums[largest]:
largest = right_child
# If the largest element is no longer the root element, swap them
if largest != root_index:
nums[root_index], nums[largest] = nums[largest], nums[root_index]
# Heapify the new root element to ensure it's the largest
heapify(nums, heap_size, largest)
def heap_sort(nums):
n = len(nums)
# Create a Max Heap from the list
# The 2nd argument of range means we stop at the element before -1 i.e.
# the first element of the list.
# The 3rd argument of range means we iterate backwards, reducing the count
# of i by 1
for i in range(n, -1, -1):
heapify(nums, n, i)
# Move the root of the max heap to the end of
for i in range(n - 1, 0, -1):
nums[i], nums[0] = nums[0], nums[i]
heapify(nums, i, 0)
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