Java vs Ruby

_problem.txt

Sort the strings by length in ascending order.
If the string has same length, sort alphabetically, ignoring case.

Input:
- first line - "n", number of strings to sort
- n following lines - the string to sort

Output:
- n lines. each line is a string, in sorted order

sort_by_length.rb

puts Array.new(gets.to_i) { gets.strip }.sort_by { |string| [string.length, string.downcase] }

SortByLength.java

import java.util.*;

public class SortByLength {
	private static Scanner scanner = new Scanner(System.in);
	public static void main(String[] args) {
		String[] strings = new String[Integer.parseInt(scanner.nextLine())];
		for (int i = 0; i < strings.length; i ++) {
			strings[i] = scanner.nextLine();
		}
		Arrays.sort(strings, new Comparator<String>() {
			@Override
			public int compare(String a, String b) {
				return a.length() == b.length() ? a.compareToIgnoreCase(b) : a.length() - b.length();
			}
		});
		for (String string : strings) {
			System.out.println("-" + string);
		}
	}
}