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    EM-algorithm coin example
  
        
  
    
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  | #!/usr/bin/env ruby | |
| =begin | |
| http://ai.stanford.edu/~chuongdo/papers/em_tutorial.pdf | |
| http://stats.stackexchange.com/questions/72774/numerical-example-to-understand-expectation-maximization | |
| http://math.stackexchange.com/questions/25111/how-does-expectation-maximization-work | |
| http://math.stackexchange.com/questions/81004/how-does-expectation-maximization-work-in-coin-flipping-problem | |
| http://www.youtube.com/watch?v=7e65vXZEv5Q | |
| =end | |
| # gem install distribution | |
| require 'distribution' | |
| # error bound | |
| EPS = 10**-6 | |
| # number of coin tosses | |
| N = 10 | |
| # observations | |
| X = [5, 9, 8, 4, 7] | |
| # randomly initialized thetas | |
| theta_a, theta_b = 0.6, 0.5 | |
| p [theta_a, theta_b] | |
| loop do | |
| expectation = X.map do |h| | |
| like_a = Distribution::Binomial.pdf(h, N, theta_a) | |
| like_b = Distribution::Binomial.pdf(h, N, theta_b) | |
| norm_a = like_a / (like_a + like_b) | |
| norm_b = like_b / (like_a + like_b) | |
| [norm_a, norm_b, h] | |
| end | |
| maximization = expectation.each_with_object([0.0, 0.0, 0.0, 0.0]) do |(norm_a, norm_b, h), r| | |
| r[0] += norm_a * h; r[1] += norm_a * (N - h) | |
| r[2] += norm_b * h; r[3] += norm_b * (N - h) | |
| end | |
| theta_a_hat = maximization[0] / (maximization[0] + maximization[1]) | |
| theta_b_hat = maximization[2] / (maximization[2] + maximization[3]) | |
| error_a = (theta_a_hat - theta_a).abs / theta_a | |
| error_b = (theta_b_hat - theta_b).abs / theta_b | |
| theta_a, theta_b = theta_a_hat, theta_b_hat | |
| p [theta_a, theta_b] | |
| break if error_a < EPS && error_b < EPS | |
| end | 
      
      
  Author
  
  
        
      
            dustalov
  
      
      
      commented 
        May 17, 2015 
      
    
  
  
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