Javascript to debug an ajax request

debug-ajax-console.js

var oXhr;

oXhr = new XMLHttpRequest();
oXhr.id = (new Date()).getTime();

oXhr.onreadystatechange = function() {
    if (oXhr.readyState === 4 && (oXhr.status === 200)) {
        // code stuffs
        console.log(this.id);
    }
};