Created
June 3, 2010 16:57
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Given: | |
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unconstrained querystring (Q), | |
zero or more chainable slices (S) to be applied on Q, | |
Range: items=A,B (R) | |
Task: | |
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determine: | |
"skip" (offset from start of Q), | |
"limit" (the final length of required recodrset, R being honored), | |
"count" (the length of constrained recodrset, which we denote as Q&S) | |
Content-Range: items=<skip>-<skip+limit-1>/<count> | |
Solution: | |
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Let's determine the result of sequential application of slices (deanlandolt, please) | |
In case when all slices have non-negative first parameters the resulting is slice(X,Y) where X=sum(Xi), Y=min(Yi-Xi) for all i. | |
So the length of the constrained (sliced) recordset is always the minimum of Y-X and len(S). That gives us | |
count := min(Y-X, len(S)) | |
and we need not calculate the len(Q&S). Thus we need not mangle the initial querystring (Q). | |
Next, trivially: | |
skip := X+A | |
Next, | |
limit := min(count,B-A+1) | |
Conclusion: | |
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Using just arithmetics, we avoided mangling query and allowed any number of slices S |
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