Generate random(ish) passwords from the cli (thanks to @markpudd for the idea)

generate_passwords.sh

#! /usr/bin/env bash

## Use openssl. Use hex not base64, special characters suck in passwords
# the number refers to the number of bytes, so with 2 hex characters per byte, this is a 32 character password.
openssl rand -hex 16

## Just straight up urandom. Give me 5 32 char alpha-numeric passwords
tr -cd '[:alnum:]' < /dev/urandom | fold -w 32 | head -n 5
tr -cd 'a-zA-Z0-9' < /dev/urandom | fold -w 32 | head -n 5

## Use gpg
# --gen-random 0,1 [count] uses /dev/urandom
# --gen-random 2 [count] uses /dev/random THIS WILL SIGNIFICATNLY DRAIN YOUR ENTROPY
# [count] is the number of bytes to pull. 1000 bytes should be enough for 5 32 char password
gpg --gen-random 1 1000 | tr -cd '[:alnum:]' | fold -w 32 | head -n 5

## XKCD-style rand word generator (assumes you have a word list in /usr/share/dict/words)
shuf -n 5 /usr/share/dict/words | sed 's/./\u&/' | tr -d "'" | tr "\n" " "
for i in {1..6}; do shuf -n 5 /usr/share/dict/words | sed 's/./\u&/' | tr -d "'" | tr "\n" " "; echo; done

## Make passwords, not phrases, and append some digits to the end
# shellcheck disable=SC2005
{ shuf -n 5 /usr/share/dict/words | sed 's/./\u&/' | tr -cd "[:alnum:]"; echo "$(printf "%05d" "$(shuf -i 0-99999 -n 1)")"; }

# shellcheck disable=SC2034
# shellcheck disable=SC2005
for i in {1..6}; do shuf -n 5 /usr/share/dict/words | sed 's/./\u&/' | tr -cd "[:alnum:]"; echo "$(printf "%05d" "$(shuf -i 0-99999 -n 1)")"; done

## If using different locales, you might need to set your locale before doing string operations
# LC_CTYPE=C