Scala "nameOf" macro: get the name of an identifier as a string at compile-time!

Macros.scala

import scala.annotation.tailrec
import scala.language.experimental.macros
import scala.reflect.macros.blackbox

// UPDATE: now published for your convenience!
//   https://github.com/dwickern/scala-nameof

object Macros {
  def nameOfImpl(c: blackbox.Context)(x: c.Tree): c.Tree = {
    import c.universe._

    @tailrec def extract(x: c.Tree): String = x match {
      case Ident(TermName(s)) => s
      case Select(_, TermName(s)) => s
      case Function(_, body) => extract(body)
      case Block(_, expr) => extract(expr)
      case Apply(func, _) => extract(func)
    }

    val name = extract(x)
    q"$name"
  }
  def nameOfMemberImpl(c: blackbox.Context)(f: c.Tree): c.Tree = nameOfImpl(c)(f)

  def nameOf(x: Any): String = macro nameOfImpl
  def nameOf[T](f: T => Any): String = macro nameOfMemberImpl
}

//
// Sample usage:
//

val someVariable = ""
Macros.nameOf(someVariable) // "someVariable"

def someFunction(x: Int): String = ???
Macros.nameOf(someFunction _) // "someFunction"

case class SomeClass(someParam: String)
val myClass = SomeClass("")
Macros.nameOf(myClass.someParam) // "someParam"

// without having an instance of the class:
Macros.nameOf[SomeClass](_.someParam) // "someParam"