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December 22, 2015 02:59
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A second version of the program in https://gist.github.com/dyoo/6407562. Make simple things more complicated! :P
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package main | |
// A question from reading Barry Schwartz's "The Paradox of Choice". | |
// | |
// How many English words start with "t"? | |
// | |
// How many English words have "t" as the third letter? | |
import ( | |
"bufio" | |
"fmt" | |
"io" | |
"os" | |
) | |
func tabulate(aReader io.Reader, preds []func(string) bool) []int { | |
counts := make([]int, len(preds), len(preds)) | |
scanner := bufio.NewScanner(aReader) | |
for scanner.Scan() { | |
nextWord := scanner.Text() | |
for i, pred := range preds { | |
if pred(nextWord) { | |
counts[i]++ | |
} | |
} | |
} | |
return counts | |
} | |
func startsWithT(s string) bool { | |
return len(s) > 0 && (s[0] == 't' || s[0] == 'T') | |
} | |
func hasTeeAsThirdLetter(s string) bool { | |
return len(s) > 2 && (s[2] == 't' || s[2] == 'T') | |
} | |
func main() { | |
counts := tabulate(os.Stdin, []func(string) bool{ | |
startsWithT, | |
hasTeeAsThirdLetter}) | |
for _, c := range counts { | |
fmt.Println(c) | |
} | |
} |
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