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Cantor pairing function
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// http://en.wikipedia.org/wiki/Pairing_function | |
package main | |
import ( | |
"fmt" | |
"math" | |
) | |
func InvertedCantorPairing(z int) (int, int) { | |
w := int(math.Floor((math.Sqrt(float64(8*z+1)) - 1) / 2)) | |
t := (w*w + w) / 2 | |
y := z - t | |
x := w - y | |
return x, y | |
} | |
func CantorPairing(k1, k2 int) int { | |
return (k1+k2)*(k1+k2+1)/2 + k2 | |
} | |
func main() { | |
for i := 0; i < 100; i++ { | |
x, y := InvertedCantorPairing(i) | |
fmt.Println(i, x, y, CantorPairing(x, y)) | |
} | |
} |
@dyarosla -- rounding down for int division, we have:
(3+3)/2 = 6/2 = 3
3/2 + 3/2 = 1 + 1 = 2
Your method works for approximate results, but not for exact ones.
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Correct me if I'm wrong, but to avoid overflow with big (k1, k2) we should use
(k1/2+k2/2)*(k1+k2+1) + k2
This is similar in nature to what you'd do for
(a+b)/2
You'd instead code it as
a/2 + b/2
Because for large (a, b), where a+b > MAX_INT, we would still get a usable result.