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January 31, 2015 21:16
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Tour of Go: Exercise: Equivalent Binary Trees
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package main | |
import ( | |
"code.google.com/p/go-tour/tree" | |
"fmt" | |
) | |
// Walk walks the tree t sending all values (sorted ascending) | |
// from the tree to the channel ch. | |
func Walk(t *tree.Tree, ch chan int) { | |
if t.Left != nil { | |
Walk(t.Left, ch) | |
} | |
ch <- t.Value | |
if t.Right != nil { | |
Walk(t.Right, ch) | |
} | |
} | |
// Same determines whether the trees | |
// t1 and t2 contain the same values. | |
func Same(t1, t2 *tree.Tree) bool { | |
ch1 := make(chan int) | |
ch2 := make(chan int) | |
go Walk(t1, ch1) // ch1 will receive all values from tree 1 (sorted) | |
go Walk(t2, ch2) // ch2 will receive all values from tree 2 (sorted) | |
for i := 0; i<10; i++ { // task clearly says it's always 10 items in tree | |
// all pairs should match | |
if <- ch1 != <- ch2 { // if not matches | |
return false // trees are not equivalent | |
} | |
} | |
return true // if we get here: trees are equivalent | |
} | |
func main() { | |
fmt.Println("1)", Same(tree.New(1), tree.New(1))) | |
fmt.Println("2)", Same(tree.New(1), tree.New(2))) | |
} |
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1) true | |
2) false |
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