Order an array of objects based on another array order

mapOrder.js

/**
 * Sort array of objects based on another array
 */

function mapOrder (array, order, key) {
  
  array.sort( function (a, b) {
    var A = a[key], B = b[key];
    
    if (order.indexOf(A) > order.indexOf(B)) {
      return 1;
    } else {
      return -1;
    }
    
  });
  
  return array;
};


/**
 * Example:
 */

var item_array, item_order, ordered_array;

item_array = [ 
  { id: 2, label: 'Two' }
, { id: 3, label: 'Three' }
, { id: 5, label: 'Five' }
, { id: 4, label: 'Four' }
, { id: 1, label: 'One'}
];

item_order = [1,2,3,4,5];

ordered_array = mapOrder(item_array, item_order, 'id');

console.log('Ordered:', JSON.stringify(ordered_array));

Finally I got what I was looking for. Thanks @kkoo95

Here is the code If you want to move unmated rest of items at the end of array.

export const mapOrder = <T>(array: T[], order: any[], key: keyof T) => {
  return array.sort((a, b) => {
    let weightA = 0;
    let weightB = 0;

    if (!order.includes(a[key])) {
      weightA += 100;
    }

    if (!order.includes(b[key])) {
      weightB += 100;
    }

    return order.indexOf(a[key]) + weightA - (order.indexOf(b[key]) + weightB);
  });
};

Test Case

 const item_array = [
    { id: 2, label: "Two" },
    { id: 3, label: "Three" },
    { id: 5, label: "Five" },
    { id: 4, label: "Four" },
    { id: 1, label: "One" }
  ];

  const item_order = [1, 5];

  const ordered_array = mapOrder(item_array, item_order, "id");
  
console.log("Ordered:", JSON.stringify(ordered_array));
// Ordered: [{"id":1,"label":"One"},{"id":5,"label":"Five"},{"id":2,"label":"Two"},{"id":3,"label":"Three"},{"id":4,"label":"Four"}]