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Problem Euler 21 - Haskell Solution
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| module Euler.Problem21 where | |
| import qualified Data.Map as Map | |
| import qualified Data.Set as Set | |
| problem1::Int->Int->Int->Int | |
| problem1 a b n = sum [x | x <- [1..n-1], x `mod` a == 0 || x `mod` b == 0] | |
| sumOfProperDivisors::Int->Int | |
| sumOfProperDivisors n = sum [x | x <- [1..n `div` 2], n `mod` x == 0] | |
| groupBySum::Int -> Map.Map Int [Int] | |
| groupBySum n | n <= 0 = Map.empty | |
| | otherwise = foldl (\acc (k,v) -> Map.insertWith (++) k [v] acc) Map.empty mapped | |
| where | |
| tuples = zip [sumOfProperDivisors x | x <- [1..]] [1..n] | |
| mapped = [ (x,y) | (x,y) <- tuples, x > 1] | |
| findAmicable::Int->Map.Map Int [Int]->Maybe(Int,Int) | |
| findAmicable n groups = case Map.lookup n groups of | |
| Just xs -> if s `elem` xs then Just (n `min` s, n `max` s) else Nothing | |
| Nothing -> Nothing | |
| where s = sumOfProperDivisors n | |
| lookupAmicables::Int->Map.Map Int [Int]->Set.Set (Int,Int) | |
| lookupAmicables n groups | n <= 0 = Set.empty | |
| | otherwise = case findAmicable n groups of | |
| Just(x,y) -> if x /= y then Set.insert (x, y) $ lookupAmicables (n - 1) groups | |
| else lookupAmicables (n - 1) groups | |
| Nothing -> lookupAmicables (n-1) groups | |
| solve::Int->Int | |
| solve n = let | |
| groups = groupBySum n | |
| in sum [x + y | (x,y) <- Set.toList (lookupAmicables n groups)] | |
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