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May 17, 2024 07:45
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HTML video play file blob object url
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<!DOCTYPE html> | |
<html lang="en"> | |
<head> | |
<meta charset="UTF-8"> | |
<title></title> | |
</head> | |
<body> | |
<video></video> | |
<br/> | |
<input type="file" name="file" id="fileItem" onchange="onChange()" > | |
<input type="submit" value="Play"> | |
</form> | |
<script type="text/javascript"> | |
var URL = window.URL || window.webkitURL; | |
var video = document.getElementsByTagName('video')[0]; | |
function onChange() { | |
var fileItem = document.getElementById('fileItem'); | |
var files = fileItem.files; | |
var file = files[0]; | |
var url = URL.createObjectURL(file); | |
video.src = url; | |
video.load(); | |
video.onloadeddata = function() { | |
video.play(); | |
} | |
} | |
</script> | |
</body> | |
</html> |
If you open blob url in new tab you just get playing video. So what the point of this method? It does not protect video from being downloaded.
How did you go about it, the video isn't playing on my end
fetch('./21745_2160p.mp4')
.then(res => res.blob()) // Gets the response and returns it as a blob
.then(blob => {
console.log(blob)
document.querySelector('#myvideo').src = URL.createObjectURL(blob);
});
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Working for me.