Created
January 22, 2014 15:12
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#include <cmath> | |
const int MAXN = 100; | |
const double EPS = 1e-10; | |
//列主元gauss消去求解a[][]x[]=b[] | |
//返回是否有唯一解,若有解在b[]中 | |
bool gaussCpivot(int n, double a[][MAXN], double b[]) { | |
int i, j, k, row; | |
double maxp, t; | |
for (k = 0; k < n; k++) { | |
for (maxp = 0, i = k; i < n; i++) { | |
if (fabs(a[i][k]) > fabs(maxp)) { | |
maxp = a[row = i][k]; | |
} | |
} | |
if (fabs(maxp) < EPS) { | |
return false; | |
} | |
if (row != k) { | |
for (j = k; j < n; j++) { | |
swap(a[k][j], a[row][j]); | |
} | |
swap(b[k], b[row]); | |
} | |
for (j = k + 1; j < n; j++) { | |
a[k][j] /= maxp; | |
for (i = k + 1; i < n; i++) { | |
a[i][j] -= a[i][k] * a[k][j]; | |
} | |
} | |
b[k] /= maxp; | |
for (i = k + 1; i < n; i++) { | |
b[i] -= b[k] * a[i][k]; | |
} | |
} | |
for (i = n - 1; i >= 0; i--) { | |
for (j = i + 1; j < n; j++) { | |
b[i] -= a[i][j] * b[j]; | |
} | |
} | |
return true; | |
} |
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