Created
August 19, 2011 18:33
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CoPL problem 71
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|- let f = fun x -> match x with [] -> 0 | a :: b -> a in | |
f (4::[]) + f [] + f (1 :: 2 :: 3 :: []) | |
evalto 5 by E-Let { | |
|- fun x -> match x with [] -> 0 | a :: b -> a | |
evalto ()[fun x -> match x with [] -> 0 | a :: b -> a] | |
by E-Fun {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
((f (4::[])) + (f [])) + (f (1 :: 2 :: 3 :: [])) | |
evalto 5 by E-Plus { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
(f (4::[])) + (f []) | |
evalto 4 | |
by E-Plus { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
f (4::[]) | |
evalto 4 by E-App { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
f evalto ()[fun x -> match x with [] -> 0 | a :: b -> a] | |
by E-Var {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
(4 :: []) | |
evalto (4 :: []) | |
by E-Cons { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
4 evalto 4 by E-Int {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
[] evalto [] by E-Nil {}; | |
}; | |
x = 4 :: [] |- | |
match x with [] -> 0 | a :: b -> a | |
evalto 4 by E-MatchCons { | |
x = 4 :: [] |- | |
x evalto 4 :: [] | |
by E-Var {}; | |
x = 4 :: [], a = 4, b = [] |- | |
a evalto 4 | |
by E-Var {} | |
} | |
}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
f [] | |
evalto 0 by E-App { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
f evalto ()[fun x -> match x with [] -> 0 | a :: b -> a] | |
by E-Var {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
[] evalto [] | |
by E-Nil {}; | |
x = [] |- | |
match x with [] -> 0 | a :: b -> a | |
evalto 0 | |
by E-MatchNil { | |
x = [] |- | |
x evalto [] | |
by E-Var {}; | |
x = [] |- | |
0 evalto 0 | |
by E-Int {} | |
} | |
}; | |
4 plus 0 is 4 by B-Plus {} | |
}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
f (1 :: 2 :: 3 :: []) | |
evalto 1 | |
by E-App { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
f evalto ()[fun x -> match x with [] -> 0 | a :: b -> a] | |
by E-Var {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
1 :: (2 :: (3 :: [])) | |
evalto 1 :: (2 :: (3 :: [])) | |
by E-Cons { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
1 evalto 1 by E-Int {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
2 :: (3 :: []) | |
evalto 2 :: (3 :: []) | |
by E-Cons { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
2 evalto 2 by E-Int {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
3 :: [] | |
evalto 3 :: [] | |
by E-Cons { | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
3 evalto 3 by E-Int {}; | |
f = ()[fun x -> match x with [] -> 0 | a :: b -> a] |- | |
[] evalto [] by E-Nil {} | |
} | |
} | |
}; | |
x = 1 :: 2 :: 3 :: [] |- | |
match x with [] -> 0 | a :: b -> a | |
evalto 1 | |
by E-MatchCons { | |
x = 1 :: 2 :: 3 :: [] |- | |
x evalto 1 :: 2:: 3 :: [] | |
by E-Var {}; | |
x = 1 :: 2 :: 3 :: [], a = 1, b = 2 :: 3 :: [] |- | |
a evalto 1 | |
by E-Var {} | |
} | |
}; | |
4 plus 1 is 5 by B-Plus {} | |
} | |
} |
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