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Quick calc to determine centerpoint and radius of circle enclosing a bounding box (helper to query Redis geospatial data)
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using System; | |
using Microsoft.SqlServer.Types; | |
using System.Data.SqlTypes; | |
namespace circleradius | |
{ | |
class Program | |
{ | |
static void Main() | |
{ | |
SqlServerTypes.Utilities.LoadNativeAssemblies(AppDomain.CurrentDomain.BaseDirectory); | |
double lat1 = 15; | |
double lng1 = 11; | |
double lat2 = 35; | |
double lng2 = 32; | |
string lineString = string.Format("LINESTRING({0} {1}, {2} {3} )",lat1,lng1,lat2,lng2); | |
string rectangle = string.Format("POLYGON(({0} {1}, {0} {3}, {2} {3}, {2} {1}, {0} {1}))", lat1, lng1, lat2, lng2); | |
//make bounding box and hypothenuse | |
SqlGeometry bbox = SqlGeometry.STGeomFromText(new SqlChars(new SqlString(rectangle)), 4326); | |
SqlGeometry bboxDiagonal = SqlGeometry.STGeomFromText(new SqlChars(new SqlString(lineString)), 4326); | |
//get half length of diagonal (1/2 hypothenuse) | |
double circleRadius = double.Parse((bboxDiagonal.STLength() / 2).ToString()); | |
//get centerpoint of bounding box | |
SqlGeometry circleCenter = bbox.STCentroid(); | |
//not necessary for further spatial work, so just here to prove calc. | |
SqlDouble a = circleCenter.STX; | |
SqlDouble b = circleCenter.STY; | |
Console.WriteLine("r="+circleRadius); | |
Console.WriteLine("centerpoint: ("+a+" "+b+")"); | |
Console.ReadLine(); | |
} | |
} | |
} |
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