Created
August 25, 2011 03:50
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Find the jQuery Bug #2: Solution
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| <ul id="numberList"> | |
| <li data-value="1">One</li> | |
| <li data-value="2">Two</li> | |
| <li data-value="3">Three</li> | |
| <li data-value="4">Four</li> | |
| <li data-value="5">Five</li> | |
| <li data-value="6">Six</li> | |
| <li data-value="7">Seven</li> | |
| <li data-value="8">Eight</li> | |
| <li data-value="9">Nine</li> | |
| <li data-value="10">Ten</li> | |
| </ul> |
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| <!DOCTYPE html> | |
| <html> | |
| <head> | |
| <script class="jsbin" src="http://code.jquery.com/jquery-1.7.1.min.js"></script> | |
| <meta charset=utf-8 /> | |
| <title>JS Bin</title> | |
| <!--[if IE]> | |
| <script src="http://html5shiv.googlecode.com/svn/trunk/html5.js"></script> | |
| <![endif]--> | |
| <style> | |
| article, aside, figure, footer, header, hgroup, | |
| menu, nav, section { display: block; } | |
| </style> | |
| </head> | |
| <body> | |
| <ul id="numberList"> | |
| <li data-value="1">One</li> | |
| <li data-value="2">Two</li> | |
| <li data-value="3">Three</li> | |
| <li data-value="4">Four</li> | |
| <li data-value="5">Five</li> | |
| <li data-value="6">Six</li> | |
| <li data-value="7">Seven</li> | |
| <li data-value="8">Eight</li> | |
| <li data-value="9">Nine</li> | |
| <li data-value="10">Ten</li> | |
| </ul> | |
| </body> | |
| </html> |
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| function listHasNumber( $list, numberToFind ) { | |
| var hasNumber = false; | |
| $list.find( "li" ).each( function() { | |
| if ( $( this ).data( "value" ) === numberToFind ) { | |
| hasNumber = true; | |
| return false; | |
| } | |
| }); | |
| return hasNumber; | |
| } | |
| var $numberList = $( "#numberList" ); | |
| console.log( listHasNumber( $numberList, 0 ) ); // false | |
| console.log( listHasNumber( $numberList, 1 ) ); // true | |
| console.log( listHasNumber( $numberList, 5 ) ); // true | |
| console.log( listHasNumber( $numberList, 10 ) ); // true | |
| console.log( listHasNumber( $numberList, 15 ) ); // false |
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