Recursive function to execute function until attempts finish or promise resolve

recursive.js

const waitFor = (delay = 0) => new Promise((resolve) => setTimeout(resolve, delay))

const recursiveToZero = (func, attempt, delay, error) => {
  if (attempt === 0) {
    throw error || new Error('Fail')
  }

  return func().catch((err) => waitFor(delay).then(() => recursiveToZero(func, attempt - 1, delay, err)))
}

export const recursive = (func, attempts = 5, delay = 0) => Promise.resolve().then(() => recursiveToZero(func, attempts, delay))

/** 
 * how to use
 */
const myFunc = () => new Promise((resolve, reject) => {
  const num = Math.floor(Math.random() * 10) + 1
  
  if (num % 2 === 0) {
    resolve()
  } else {
    reject()
  }
})

recursive(myFunc, 3, 3000)
  .then(() => console.log('success'))
  .catch(() => console.log('error'))

recursive.ts

const waitFor = (delay: number = 0): Promise<any> => new Promise((resolve) => setTimeout(resolve, delay))

const recursiveToZero = (func: () => Promise<any>, attempt: number, delay: number, error?: any): Promise<any> => {
  if (attempt === 0) {
    throw error || new Error('Fail')
  }

  return func().catch((err) => waitFor(delay).then(() => recursiveToZero(func, attempt - 1, delay, err)))
}

export const recursive = (func: () => Promise<any>, attempts: number = 5, delay: number = 0) => Promise.resolve().then(() => recursiveToZero(func, attempts, delay))

/** 
 * how to use
 */
const myFunc = (): Promise<any> => new Promise((resolve, reject) => {
  const num = Math.floor(Math.random() * 10) + 1
  
  if (num % 2 === 0) {
    resolve()
  } else {
    reject()
  }
})

recursive(myFunc, 3, 3000)
  .then(() => console.log('success'))
  .catch(() => console.log('error'))