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private static final long addressOffset; | |
static { | |
try { | |
addressOffset = UnsafeAccess.unsafe.objectFieldOffset(Buffer.class.getDeclaredField("address")); | |
} catch (Exception e) { | |
throw new RuntimeException(e); | |
} | |
} | |
public static long getAddress(ByteBuffer buffy) { | |
// steal the value of address field from Buffer, holding the memory address for this ByteBuffer | |
return UnsafeAccess.unsafe.getLong(buffy, addressOffset); | |
} | |
public static ByteBuffer allocateAlignedByteBuffer(int capacity, long align) { | |
// Power of 2 --> single bit, none power of 2 alignments are not allowed. | |
if (Long.bitCount(align) != 1) { | |
throw new IllegalArgumentException("Alignment must be a power of 2"); | |
} | |
// We over allocate by the alignment so we know we can have a large enough aligned | |
// block of memory to use. Also set order to native while we are here. | |
ByteBuffer buffy = ByteBuffer.allocateDirect((int) (capacity + align)); | |
long address = getAddress(buffy); | |
// check if we got lucky and the address is already aligned | |
if ((address & (align - 1)) == 0) { | |
// set the new limit to intended capacity | |
buffy.limit(capacity); | |
// the slice is now an aligned buffer of the required capacity | |
return buffy.slice().order(ByteOrder.nativeOrder()); | |
} else { | |
// we need to shift the start position to an aligned address --> address + (align - (address % align)) | |
// the modulo replacement with the & trick is valid for power of 2 values only | |
int newPosition = (int) (align - (address & (align - 1))); | |
// change the position | |
buffy.position(newPosition); | |
int newLimit = newPosition + capacity; | |
// set the new limit to accomodate offset + intended capacity | |
buffy.limit(newLimit); | |
// the slice is now an aligned buffer of the required capacity | |
return buffy.slice().order(ByteOrder.nativeOrder()); | |
} | |
} |
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