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Resolução do Exercício 02 do Capítulo 03 - JavaScript Eloquente
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| var limite = 100, | |
| contador = 1; | |
| for ( ; contador <= limite; contador += 1 ) { | |
| if ( contador % 3 === 0 && contador % 5 === 0 ) { | |
| console.log( "FizzBuzz" ); | |
| } else if ( contador % 3 === 0 ) { | |
| console.log( "Fizz" ); | |
| } else if ( contador % 5 === 0 ) { | |
| console.log( "Buzz" ); | |
| } | |
| console.log( contador ); | |
| } |
leanfj
commented
Apr 17, 2019
for(x = 1; x <= 100; x++){
if(x % 3 == 0){
console.log("Fizz")
}else if(x % 5 == 0){
console.log("Buzz");
}else{
console.log(x);
}
}
console.log("-----------------")
for(y = 1; y <= 100; y++){
if(y % 3 == 0 || y % 5 == 0){
console.log("FizzBuzz")
}else{
console.log(y);
}
}
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