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MCMC for simple marketing data
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import pymc, pymc.graph | |
import matplotlib.pyplot as plt | |
import numpy as np | |
import sys | |
channels = [ | |
('A', 2292.04, 9), | |
('B', 1276.85, 2), | |
('C', 139.59, 3), | |
('D', 954.98, 5) | |
] | |
n_burn, n_samples = 1000, int(sys.argv[1]) | |
for channel, spend_obs, transactions_obs in channels: | |
# Let's say the cost per lead is uniform between 0 and 100000 | |
# pymc forces you to pick an upper bound, so let's pick a silly one | |
c = pymc.Uniform('c', 0, 100000) | |
# Now let's assume the *expected* number of transactions is really just | |
# the total number of money spent divided by the cost per lead | |
@pymc.deterministic | |
def e(c=c): | |
return spend_obs / c | |
# The observed number of transactions is a Poisson with mu set to the expectations | |
a = pymc.Poisson('a', mu=e, observed=True, value=transactions_obs) | |
model = pymc.MCMC([c, e, a]) | |
graph = pymc.graph.graph(model) | |
graph.write_png("graph.png") | |
model.sample(n_samples, n_burn) | |
ys, xs = np.histogram(model.trace('c')[:], range=(0, 500), bins=100) | |
xs = (xs[1:] + xs[:-1])/2 | |
plt.plot(xs, ys) | |
plt.legend([c for c, _, _ in channels]) | |
plt.gca() | |
plt.title('%d samples (%d burn)' % (n_samples, n_burn)) | |
plt.xlabel('Cost per transaction') | |
plt.ylabel('Probability density') | |
plt.savefig('marketing_mc_%09d.png' % n_samples) |
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