"Copy to cURL" in Chrome to Apache Bench command -- Script for Python3

curl_to_ab.py

#!/usr/bin/env python3
import sys
import os


def curl_to_ab(curl_cmd: list, num: int=200, cur: int=4) -> str:
    """
    Translate a cURL command created by Chrome's developer tools into a
    command for ``ab``, the ApacheBench HTTP benchmarking tool.

    Parameters
    ----------
    curl_cmd
        The string given to you by the "Copy to cURL" context action in
        Chrome's developer tools.
    num : int
        The number of requests ApacheBench should make in total
    cur : int
        The number of concurrent requests ApacheBench should make

    Note
    ----
    Not all headers play nice with ApacheBench, so ``headers_to_copy`` has
    been set to a reasonable default. Tweak this if you need something
    else in there.
    """
    url = curl_cmd[1]
    headers_to_copy = [
        'Origin',
        'Authorization',
        'Accept',
        'Cookie',
        'User-Agent',
        'Accept-Encoding',
        'Accept-Language',
        'Upgrade-Insecure-Requests'
    ]
    headers = []

    for i, part in enumerate(curl_cmd):
        if part == '-H':
            header = curl_cmd[i+1]
            if any([h in header for h in headers_to_copy]):
                headers.append("'{}'".format(header))

    cmd = ['ab -n {} -c {}'.format(num, cur)]
    cmd += ['-H {}'.format(part) for part in headers]
    cmd.append("'{}'".format(url))

    return ' '.join(cmd)


if __name__ == '__main__':
    """Usage: python curl_to_ab.py <cURL command from Chrome>
    """
    os.system(curl_to_ab(sys.argv[1:]))

I try running
python curl_to_ab.py curl 'http://test.awesomesite.id'

but get this

  File "curl_to_ab.py", line 6
    def curl_to_ab(curl_cmd: list, num: int=200, cur: int=4) -> str:
                           ^
SyntaxError: invalid syntax

@Myusuf060696 The problem is that you are trying to use Python 2, not Python 3. Try with Python 3.

Run python3 curl_to_ab.py

and get following errors:

Traceback (most recent call last):
  File "curl_to_ab.py", line 56, in <module>
    os.system(curl_to_ab(sys.argv[1:]))
  File "curl_to_ab.py", line 27, in curl_to_ab
    url = curl_cmd[1]
IndexError: list index out of range