Created
December 5, 2014 22:15
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Clang Optimisation Bug
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#include <stdio.h> | |
#include <stdlib.h> | |
#include <sys/time.h> | |
int sum(int a, int b, int c, int d) { | |
return a + b + c + d; | |
} | |
int product(int a, int b, int c, int d) { | |
return a * b * c * d; | |
} | |
int expression(int x) { | |
return (x ? sum : product)(1, 2, 3, 4); | |
} | |
int statement(int x) { | |
if (x) | |
return sum(1, 2, 3, 4); | |
else | |
return product(1, 2, 3, 4); | |
} | |
int main() { | |
int i; | |
struct timeval | |
start_expression, | |
end_expression, | |
start_statement, | |
end_statement; | |
double | |
elapsed_expression, | |
elapsed_statement; | |
int x = 0; | |
const int samples = 10000000; | |
srand(time(NULL)); | |
gettimeofday(&start_expression, NULL); | |
for (i = 0; i < samples; ++i) | |
x += expression(rand() & 1); | |
gettimeofday(&end_expression, NULL); | |
printf("%d\n", x); | |
x = 0; | |
gettimeofday(&start_statement, NULL); | |
for (i = 0; i < samples; ++i) | |
x += statement(rand() & 1); | |
gettimeofday(&end_statement, NULL); | |
printf("%d\n", x); | |
elapsed_statement | |
= (double)end_statement.tv_sec | |
+ (double)end_statement.tv_usec * 1e-6 | |
- (double)start_statement.tv_sec | |
- (double)start_statement.tv_usec * 1e-6; | |
elapsed_expression | |
= (double)end_expression.tv_sec | |
+ (double)end_expression.tv_usec * 1e-6 | |
- (double)start_expression.tv_sec | |
- (double)start_expression.tv_usec * 1e-6; | |
printf( | |
"expression: %.2f\n" | |
"statement: %.2f\n" | |
"expression is %.2f%% slower than statement\n", | |
elapsed_statement, | |
elapsed_expression, | |
100 * (elapsed_expression - elapsed_statement) / elapsed_statement | |
); | |
return 0; | |
} |
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