Solution of: https://stackoverflow.com/questions/46456703/translate-pseudocode-into-python-secant-method/46457259#46457259

main.py

from math import *

def f(x: float) -> float:
    return exp(x) - sin(x)

def secant(x0: float, x1: float, f, epsilon: float, delta: float, iter_max: int) -> float:
    fx0 = f(x0)
    fx1 = f(x1)
    print("{0} {1:.20f} {2:.20f}".format(0, x0, fx0))
    if iter_max == 0:
        return 0, x0, fx0
    print("{0} {1:.20f} {2:.20f}".format(1, x1, fx1))
    if iter_max == 1:
        return 1, x1, fx1



    for k in range(2, iter_max):
        if abs(fx0) > abs(fx1):
            tmp =  x0
            x0 = x1
            x1 =tmp
            tmp = fx0
            fx0 = fx1
            fx1 = tmp

        s = (x1 - x0) / (fx1 - fx0)
        x1 = x0
        fx1 = fx0
        x0 = x0 - fx0 * s
        fx0 = f(x0)
        print("{0} {1:.20f} {2:.20f}".format(k, x0, fx0))
        if abs(fx0) < epsilon or abs(x1 - x0)  <= delta:
            break
    return k, x0, fx0
            

root = secant(-3.5, -2.5, f, 0.0000000000000000000001, 0.000001, 100)