Created
August 8, 2011 03:16
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if-else style comparison
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// #1 | |
void add_node(Node *node, Node *new_node) { | |
if (new_node->value <= node->value) { | |
if (node->left == NULL) { | |
node->left = new_node; | |
return; | |
} | |
add_node(node->left, new_node); | |
return; | |
} | |
if (node->right == NULL) { | |
node->right = new_node; | |
return; | |
} | |
add_node(node->right, new_node); | |
} | |
// #2 | |
void add_node(Node *node, Node *new_node) { | |
if (new_node->value <= node->value) { | |
if (node->left == NULL) { | |
node->left = new_node; | |
} else { | |
add_node(node->left, new_node); | |
} | |
} else { | |
if (node->right == NULL) { | |
node->right = new_node; | |
} else { | |
add_node(node->right, new_node); | |
} | |
} | |
} |
遇到不方便 return 時, 我通常會將那段 code 抽成一個小函式, 這樣就能用 return 了
// #3
void add_node(Node *node, Node *new_node) {
if (new_node->value <= node->value) {
if (node->left == NULL) {
node->left = new_node;
} else {
add_node(node->left, new_node);
}
} else {
if (node->right == NULL) {
node->right = new_node;
} else {
add_node(node->right, new_node);
}
}
// run the code anyway.
// how to early return with sub-function?
}
void _add_node(Node *node, Node *new_node); // this is exactly the same as the old add_node()
void add_node(Node *node, Node *new_node) {
_add_node(node, new_node);
// the following codes can return as you wish.
}
不用 recursive 的寫法
不知道這樣寫有沒有錯 @@"
// #3
Node *root_node;
void add_node( Node *new_node )
{
Node **pnode = &root_node;
while( (*pnode) != NULL ) {
if( new_node->value <= (*pnode)->value )
pnode = &((*pnode)->left);
else
pnode = &((*pnode)->right);
}
(*pnode) = new_node;
}
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比较喜欢第1种,不过有时候不能 return,只能使用第2种了。