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Detect if a given word is prime according to their letter positions in alphabet.
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var alphabet = [ | |
'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', | |
'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', | |
'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', | |
'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z' | |
]; | |
// get char position in array | |
function stringToNumber (string) { | |
var number = 0; | |
for ( var i = 0, l = string.length; i < l; i++ ) { | |
var indexOfChar = alphabet.indexOf(string[i]) + 1; | |
number = number + indexOfChar; | |
} | |
return number; | |
} | |
// detect if a given number is prime | |
function isPrime (word, number) { | |
console.log('Valor: ' + number); | |
var result; | |
if (number === 1) { | |
// 1 will never be prime | |
result = false; | |
} else if (number === 2) { | |
// 2 is the only even number to be prime | |
result = true; | |
} else { // if number is not 1 or 2.... | |
// test if it is even | |
if ( number % 2 === 0 ) { | |
// number can't be divisible by any other number unless 1 or itself | |
// the only even number is 2 | |
result = false; | |
} else { | |
// loop start at 2 and ends at "number - 1" | |
// We do this trick because every number can be divided by 1 and itself | |
for (var i = 2; i < number; i++) { | |
// number can't be divisible by any other number unless 1 or itself | |
if ( number % i === 0 ) { | |
result = false; | |
// exit loop | |
break; | |
} else { | |
// aha, we got a prime number | |
result = true; | |
} | |
} | |
} | |
} | |
if (result) { | |
console.log(word + ' IS a prime word'); | |
} else { | |
console.log(word + ' IS NOT a prime word'); | |
} | |
} | |
var wordToTest = 'Fernando'; | |
// returns 103 | |
var number = stringToNumber(wordToTest); | |
// arguments('Fernando', 103) | |
isPrime(wordToTest, number); |
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