Created
February 8, 2020 05:09
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Chudnovskyの公式を用いた円周率の計算
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import Data.Bits | |
import Control.Parallel | |
cutoff = 1000000 | |
rsqrt2 :: Int -> Int -> Integer | |
rsqrt2 d n = iter 32 $ (floor $ approx * 2 ** 64) `shiftL` (d - 64) | |
where | |
approx = 1.0 / sqrt (fromIntegral n :: Double) | |
mult x y = (x * y) `shiftR` d | |
iter p x | |
| p >= d = x | |
| otherwise = iter (p * 2) ((3 * x - toInteger n * x `mult` x `mult` x) `shiftR` 1) | |
series :: Integer -> Integer -> (Integer, Integer, Integer) | |
series l r | |
| r - l == 1 = | |
let pr = (2 * r - 1) * (6 * r - 5) * (6 * r - 1) | |
qr = r * r * r * 10939058860032000 | |
ar = (if even r then 1 else -1) * (13591409 + 545140134 * r) | |
in (pr, qr, ar * pr) | |
| cutoff <= r - l = | |
let m = (r + l) `div` 2 | |
s1 = series l m | |
s2 = series m r | |
(p1, q1, t1) = s1 | |
(p2, q2, t2) = s2 | |
in s1 `par` (s2 `pseq` (p1 * p2, q1 * q2, t1 * q2 + p1 * t2)) | |
| otherwise = | |
let m = (r + l) `div` 2 | |
(p1, q1, t1) = series l m | |
(p2, q2, t2) = series m r | |
in (p1 * p2, q1 * q2, t1 * q2 + p1 * t2) | |
main :: IO () | |
main = do | |
s <- getLine | |
let n = read s | |
n2 = (+ 1024) $ ceiling $ fromIntegral n * logBase 2 10 | |
se = series 0 $ (n + 13) `div` 14 | |
r = rsqrt2 n2 10005 | |
(_, q, t) = se | |
putStrLn $ show $ s `par` (r `pseq` (((4270934400 * r * q) `div` (t + 13591409 * q)) * 10 ^ n) `shiftR` n2) |
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