Gulp config for require all tasks from a gulp-tasks dir

gulpfile.js

const gulp = require('gulp');
const path = require('path');
const fs = require('fs');

const tasks = fs.readdirSync('./gulp-tasks/');

let tasksName = [];

tasks.forEach( (task, i) => {
    const taskName = task.split('.')[0];
    tasksName[i] = taskName;
	require(path.join(__dirname, 'gulp-tasks', task));
});

gulp.task('default', tasksName);