jq - notes

Jq notes

Show names and ids of all efs file systems
  $ aws efs describe-file-systems | jq '.FileSystems[] | {FileSystems: .Name, FileSystemId}'


Select a single file system based on its name tag,

	$ aws efs describe-file-systems | jq '.FileSystems[] | select(.Name == "my_fs_name")'



Using two select statements for two fields returns two identical records (?)

aws efs describe-file-systems | jq '.FileSystems[] | select(.Name | contains("my_fs_name")), select(.FileSystemId | contains("fs-00000000"))'


Return the fs record only if both fields match,

$ aws efs describe-file-systems | jq '.FileSystems[] | select(.Name == "my_fs_name") | select(.FileSystemId | contains("fs-00000000"))?'


Doing it with grep and awk

-	$aws efs describe-file-systems | jq '.FileSystems[] | select(.Name == "my_fs_name")' | grep FileSystemId | awk -F':' '{print $2}' | awk -F"\"" '{print $2}'

Only return a value if both the file system name and the file system id match the given values,

-	$ aws efs describe-file-systems | jq '.FileSystems[] | select(.Name == "my_fs_name")' | jq '. | select(.FileSystemId == "fs-000000000")'

Show just the filesystem if,

-	$ FSID=$( aws efs describe-file-systems | jq '.FileSystems[] | select(.Name == "my_ef_name")' | jq '. | .FileSystemId')
-	$  echo ${FSID:1:11}

Or just do it with sed,

-	$ FSID=$(aws efs describe-file-systems | jq '.FileSystems[] | select(.Name == "my_ef_name")' | jq '. | .FileSystemId' | sed -e s/\"//g)