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format hex string using awk
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| #!/bin/sh | |
| awk '{ | |
| split($0, chars, ""); | |
| for (i=1; i<=length($0); i++) { | |
| if (flagInLine == 0) { printf ("%-5d", i/32); flagInLine=1 } | |
| printf("%s%s ", chars[i], chars[i+1]); | |
| if ((i+1) % 32 == 0) { flagInLine=0; printf "\n"} | |
| i++ | |
| } | |
| }' |
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