Created
April 27, 2013 13:10
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| 145750 flavius │ Hi. How to count the number of files in a directory (for a conditional "if there are any files in the directory, do │ Chiku|dc | |
| │ this"), without spawning a subprocess like ls? │ chris2 | |
| 145938 ccxCZ │ > files=( *(N) ); echo $#files │ Chryyz | |
| 145939 SweetieBot │ ccxCZ: 0 │ chutzpah | |
| 150011 ccxCZ │ though that doesn't get .files │ cinch | |
| 150111 flavius │ ccxCZ: and where do I put the path to the directory? │ claytron | |
| 150114 Mikachu │ (DN) │ cod3r | |
| 150123 Mikachu │ /the/directory/*(DN) │ Codynyx | |
| 150216 flavius │ so in the end: files=( ~/test/*(DN) ); if [[ $#files ]] │ Corey | |
| 150239 m0viefreak │ that would be true even when there are 0 files │ crazedpsyc | |
| 150251 flavius │ -gt 0 maybe │ crees | |
| 150252 m0viefreak │ files=( ~/test/*(DN) ); if (( files )) │ cschneid | |
| 150338 flavius │ then why not if (( ( ~/test/*(DN) ) )) ? │ cxreg | |
| 150338 m0viefreak │ always use an arithmetic context (( )) when doing match or comparing numbers │ danielsh | |
| 150410 m0viefreak │ oh │ dario | |
| 150415 m0viefreak │ files=( ~/test/*(DN) ); if (( $#files )) │ DarthGandalf | |
| 150510 flavius │ is it possible to squeeze the two statements into one, count via $# and also do the glob search? │ dbr | |
| 150556 Mikachu │ if you want nonempty, just use /path/to/dir(F) │ der-onkel | |
| 150606 Mikachu │ FN of course │ derf0 ▼ |
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