Created
October 30, 2015 04:56
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var T = [ | |
[ 1, 2, 3 ], | |
[ 2, 2, 2 ], | |
[ 3, 2, 1 ] | |
] | |
var symbols = [ 1, 2, 3 ] | |
function translateToProduct (k, i, ps) { | |
// i says where to start partitioning | |
// k says how many partitions | |
var a = 0, b = 1, c = 2, d = 4 | |
, ab = k | |
while (ab > 0) { | |
if ( i % 2 == 1 ) { | |
T [a] [ T [b] [c] ] | |
T [ T [a] [b] ] [c] | |
} else { | |
T [ T [a] [b] ] [ T [c] [d] ] | |
T [ T [a] [ T [b] [c] ] ] [d] | |
T [a] [ T [ T [b] [c] ] [d] ] | |
} | |
} | |
return t_pos | |
} | |
function canMakeProduct (ps, t) { | |
var n = ps.length | |
, k_max = n / 2 | |
, memo = [] | |
, i, k | |
memo[n] = [] | |
for (i = 0; i < n; i ++) { | |
memo[n].push(0) | |
memo[i] = [ 0 ] | |
} | |
for (i = n - 1; i >= 0; i--) { | |
for (k = 0; k < n; k ++) { | |
var t_pos = translateToProduct(k, i, ps) | |
if (t_pos == t) { | |
memo[i][k] = 1 | |
} else { | |
memo[i][k] = (memo[i + 1][k] || memo[i][k - 1]) ? 1 : 0 | |
} | |
} | |
} | |
console.log(memo) | |
return memo[0][n - 1] | |
} | |
canMakeProduct([ 1, 2, 3 ], 3) |
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