mix.rb

module Numbers
  def foo
    2
  end

  def bar
    foo * 2
  end
end

class Something
  mix Numbers, :foo => :numeric_foo

  def foo
    "foo"
  end
end

# So now…
Something.new.bar #=> 4

# Or
Something.new.bar #=> "foofoo"

Don't you mean:

# So now…
Something.new.bar #=> 4

# Or
Something.new.bar #=> "foofoo"

FWIW, from what I gleaned from the slides I'd expect:

class Something
  mix Numbers, :foo => :numeric_foo

  def foo
    "foo"
  end
end

# So now…
Something.new.bar #=> 4

Because in this case bar is calling numeric_foo. If you wanted to override foo that bar was calling then you'd do something like this:

class Something
  mix Numbers

  def foo
    "foo"
  end
end

# So now…
Something.new.bar #=> "foofoo"

Because you mix the Numbers module in before the foo method exists, there is no conflict. But, we really don't know yet. :)

Ah, yes, I meant Something.new.bar :)

If you don't override the method, it will blow up, so your second example should be mix Numbers, :foo => nil, but yeah, it's a good point. My personal expectation, is that it should return 4, not "foofoo", because it would only make sense. But that's just me :)

The code executes from top to bottom. The mix happens before foo is defined. The mix call will error if it is mixing in a method that already exists, but in your example the foo method doesn't exist yet. I think you would only need to set foo to nil if it was like this:

class Something
  def foo
    "foo"
  end

  mix Numbers, foo:nil
end

# So now…
Something.new.bar #=> "foofoo"

Just my understanding so far. I could very well be wrong.