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The reflection of f(x) in the vertical line x=k is given by f(2k-x)
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Produce a new function which is a horizontal reflection of the function f{x} in the vertical line x=k. | |
There are three steps: (1) horizontally translate the function in such a way that the reflection can be applied across the | |
Y-axis (i.e. all points on the translated function's curve should be the same distance from the Y-axis as they originally | |
were from the line x=k); (2) perform a reflection across the Y-axis; (3) reverse the translation made in step 1. | |
1. Consider the translation necessary to make the line x=k coincide with the Y-axis. Apply this translation to f{x} | |
producing f₁{x}. | |
f₁{x} = f{x+k} | |
2. Apply a reflection across the Y-axis to f₁{x} producing f₂{x}. | |
f₂{x} = f₁{-x} | |
= f{k-x} | |
3. Consider the opposite translation to that performed in step 1. Apply this translation to f₂{x} producing f₃{x}. | |
f₃{x} = f₂{x-k} | |
= f{k-{x-k}} | |
= f{2k-x} | |
The horizontal reflection of the function f{x} in the vertical line x=k is given by f{2k-x}. | |
Example. | |
Let f{x}=e^(3-x) and let r{x} be the reflection of f{x} in the line x=-4. Find r{x} in terms of x. | |
r{x} = f{2k-x}, where k=-4 | |
= f{-8-x} | |
= e^(3-(-8-x)) | |
= e^(11+x) |
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