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round robin scheduling algorithm (Linux)
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// Run VS dev terminal: start button -> serch "dev" -> start VS developer terminal | |
// Compile with: cl rr_win.c | |
// http://www.ssau.ru/files/education/metod_1/%D0%9A%D1%83%D0%BF%D1%80%D0%B8%D1%8F%D0%BD%D0%BE%D0%B2%20%D0%90.%D0%92.%20%D0%90%D0%BB%D0%B3%D0%BE%D1%80%D0%B8%D1%82%D0%BC%D1%8B%20%D0%BF%D0%BB%D0%B0%D0%BD%D0%B8%D1%80%D0%BE%D0%B2%D0%B0%D0%BD%D0%B8%D1%8F.pdf | |
#include<stdio.h> | |
#include<stdlib.h> | |
#include<ncurses.h> | |
int main() | |
{ | |
int i,j,n,bu[10],wa[10],tat[10],t,ct[10],max; | |
float awt=0,att=0,temp=0; | |
system("clear"); | |
printf("Введите количество процессов -- "); | |
scanf("%d",&n); | |
for(i=0;i<n;i++) | |
{ | |
printf("\nEnter Burst Time for process %d -- ", i+1); | |
scanf("%d",&bu[i]); | |
ct[i]=bu[i]; | |
} | |
printf("\nEnter the size of time slice -- "); | |
scanf("%d",&t); | |
max=bu[0]; | |
for(i=1;i<n;i++) | |
if(max<bu[i]) | |
max=bu[i]; | |
for(j=0;j<(max/t)+1;j++) | |
for(i=0;i<n;i++) | |
if(bu[i]!=0) | |
if(bu[i]<=t) | |
{ | |
tat[i]=temp+bu[i]; | |
temp=temp+bu[i]; | |
bu[i]=0; | |
} | |
else | |
{ | |
bu[i]=bu[i]-t; | |
temp=temp+t; | |
} | |
for(i=0;i<n;i++) | |
{ | |
wa[i]=tat[i]-ct[i]; | |
att+=tat[i]; | |
awt+=wa[i]; | |
} | |
printf("\nThe Average Turnaround time is -- %f",att/n); | |
printf("\nThe Average Waiting time is -- %f",awt/n); | |
printf("\n"); | |
printf("\n\tPROCESS\t BURST TIME \t WAITING TIME\tTURNAROUND TIME\n"); | |
for(i=0;i<n;i++) | |
printf("\t%d \t %d \t\t %d \t\t %d \n",i+1,ct[i],wa[i],tat[i]); | |
getch(); | |
} |
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