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1.6 Given an image represented by an NxN matrix, where each pixel in the image is 4 bytes, write a method to rotate the image by 90 degrees. Can you do this in place?
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#include<iostream> | |
using namespace std; | |
const int N = 4; | |
void rotate(int matrix[][N]) | |
{ | |
for (int i = 0; i < N/2; i++) { | |
for (int j = i; j < N-1-i; j++) { | |
int temp = matrix[i][j]; | |
matrix[i][j] = matrix[N-1-j][i]; | |
matrix[N-1-j][i] = matrix[N-1-i][N-1-j]; | |
matrix[N-1-i][N-1-j] = matrix[j][N-1-i]; | |
matrix[j][N-1-i] = temp; | |
} | |
} | |
} | |
void rotate0(int matrix[][N]) | |
{ | |
for (int layer = 0; layer < N/2; layer++) { | |
int first = layer; | |
int last = N-1-layer; | |
for (int i = first; i < last; i++) { | |
int offset = i - first; | |
// save top | |
int top = matrix[first][i]; | |
// left -> top | |
matrix[first][i] = matrix[last-offset][first]; | |
// bottom -> left | |
matrix[last-offset][first] = matrix[last][last-offset]; | |
// right -> bottom | |
matrix[last][last-offset] = matrix[i][last]; | |
// top -> right | |
matrix[i][last] = top; | |
} | |
} | |
} | |
void print(int matrix[][N]) | |
{ | |
for (int nRow = 0; nRow < N; nRow++) | |
{ | |
for (int nCol = 0; nCol < N; nCol++) | |
cout << matrix[nRow][nCol] << "\t"; | |
cout << endl; | |
} | |
} | |
int main(int argc, char *argv[]) | |
{ | |
int m[][N]{{1,2,3,4},{5,6,7,8},{9,10,11,12},{13,14,15,16}}; | |
print(m); | |
cout << endl; | |
rotate(m); | |
print(m); | |
return 0; | |
} |
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