Robofont: which shortkeys are assigned to what action?

find_shortkeys.py

'''
Robofont: which shortkeys are assigned to what action?
'''

import AppKit
import itertools
import mojo

modifiers = {
    AppKit.NSEventModifierFlagOption: '⌥',
    AppKit.NSEventModifierFlagCommand: '⌘',
    AppKit.NSEventModifierFlagControl: '^',
    AppKit.NSEventModifierFlagShift: '⇧',
}

key_codes = {
    # no idea how to get to those key codes in a smarter way
    '\uf700': '↑',
    '\uf701': '↓',
    '\uf72c': '⇞',
    '\uf72d': '⇟',
}

for i in range(1, len(modifiers) + 1):
    # calculcate key codes for all possible combinations of modifier keys
    for key_combination in itertools.combinations(modifiers.keys(), i):
        key_labels = [modifiers.get(key_code) for key_code in key_combination]
        key_code = sum(key_combination)
        key_codes[key_code] = ' + '.join(key_labels)

shortcuts = mojo.UI.getMenuShortCuts()
menu_dict = {}
for menu_path, key_sequence in shortcuts.items():
    readable_key_sequence = ' + '.join(
        [key_codes.get(k, str(k)) for k in key_sequence])
    joined_menu_path = ' > '.join(menu_path)
    menu_dict[f'{readable_key_sequence}'] = f'{joined_menu_path}'

longest_command = max([len(command) for command in menu_dict.keys()])
mojo.UI.OutputWindow().clear()

# sorted by action
# for key_sequence, menu_path in sorted(
#     menu_dict.items(), key=lambda item: item[1]
# ):
#     print(key_sequence.rjust(longest_command), ':', menu_path)

# # sorted by shortcut
for key_sequence, menu_path in sorted(
    menu_dict.items()
):

    print(key_sequence.rjust(longest_command), ':', menu_path)

mojo.UI.OutputWindow().show()