Created
September 9, 2022 08:02
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Non-strict evaluation in Scala
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/** | |
* Try to solve this puzzle only by modifying the function [[doubleMessage]]. | |
* All checks should succeed. | |
* | |
* This exercise must be run in a worksheet. | |
* - One is available on the Web with Scastie (https://scastie.scala-lang.org) | |
* - One is available in IntelliJ IDEA | |
* (https://www.jetbrains.com/help/idea/work-with-scala-worksheet-and-ammonite.html) | |
* | |
* Click on "> Run". See the results in the console. And try to solve this | |
* puzzle by using call-by-value and lazy declaration. | |
*/ | |
def doubleMessage(displayIt: Boolean, message: => String): String = | |
if (displayIt) | |
s"$message $message" | |
else | |
"(nope)" | |
// vvvv DON'T TOUCH THIS vvvv | |
object MessageCheck: | |
def check(description: String, condition: Boolean): Unit = | |
if (condition) | |
println(s"$description: ${Console.GREEN}Success${Console.RESET}") | |
else | |
println(s"$description: ${Console.RED}Failure${Console.RESET}") | |
private var x = 0 | |
def message = { | |
x += 1 | |
"hello" | |
} | |
def run: Unit = | |
check("should answer (nope) when no display", doubleMessage(displayIt = false, message) == "(nope)") | |
check("x should not have increased", x == 0) | |
check("should answer message twice when display", doubleMessage(displayIt = true, message) == "hello hello") | |
check("x should have increased only once", x == 1) | |
MessageCheck.run |
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