Created
September 3, 2013 06:51
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某クロッシング問題をmerge sortで解いてみた: ( https://codeiq.jp/ace/yuki_hiroshi/q432 )
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#!/usr/env/ruby -v | |
require 'benchmark' | |
measure = Benchmark.measure { | |
@crossing_count = 0 | |
def merge(a, b) | |
sorted = [] | |
until (a.empty? || b.empty?) | |
if a.first < b.first | |
sorted << a.shift | |
else | |
@crossing_count += a.size | |
sorted << b.shift | |
end | |
end | |
sorted += a + b | |
end | |
def merge_sort(array) | |
return array if array.size == 1 | |
center = array.size / 2 | |
a = merge_sort(array[0...center]) | |
b = merge_sort(array[center..-1]) | |
merge(a, b) | |
end | |
INPUT = 'crossing.txt' | |
rays = [] | |
open(INPUT).read.each_line { |line| | |
rays << line.chomp.to_i | |
} | |
merge_sort(rays) | |
p @crossing_count | |
} | |
puts Benchmark::CAPTION | |
puts measure #=> 1.4秒ぐらい |
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