Created
June 28, 2012 03:02
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#include<math.h> | |
#include<stdio.h> | |
#include<stdlib.h> | |
int prime_bound(int n) | |
{ | |
return n / log(n) + (n / log(n) / log(n)); | |
} | |
int powmod(int b, int e, int m) | |
{ | |
int accum; | |
for (accum=1; e > 0; e>>=1) | |
{ | |
if (e & 1) accum = accum * b % m; | |
b = (b * b) % m; | |
} | |
return accum; | |
} | |
int ds[] = {2, 7, 61, 0}; | |
int is_prime(int n) | |
{ | |
int m = n - 1; | |
int s; | |
int i, j; | |
for (s=0;m % 2 == 0;s++) m >> 1; | |
for (i=2;ds[i];i++) | |
{ | |
if (powmod(ds[i], m, n) != 1) | |
{ | |
for (j=0;j<s;j++) | |
{ | |
if (powmod(ds[i], m * (1 << j), n) == n - 1) | |
{ | |
return 1; | |
} | |
} | |
} | |
} | |
return 0; | |
} | |
void show_prime(int bound) | |
{ | |
int primes[257] = {}; | |
int i, n; | |
if (primes == 0) return; | |
primes[0] = 2; | |
printf("%d\n", primes[0]); | |
for (n=3; n <= bound; n+=2) | |
{ | |
for (i=1; primes[i]; i++) | |
{ | |
if (n % primes[i] == 0) break; | |
} | |
if (primes[i] == 0) | |
{ | |
if (i < 256) | |
{ | |
primes[i] = n; | |
printf("%d\n", n); | |
} | |
else if (is_prime(n)){ | |
printf("%d\n", n); | |
} | |
} | |
} | |
} | |
int main() | |
{ | |
show_prime(2147483647); | |
} |
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