Swift Exercises

fizzbuzz.swift

/*
   Write a function that prints the numbers from 1 to 100. EXCEPT:
      * If the number if a multiple of 3, print "Fizz" instead of the number
      * If the number is a multiple of 5, print "Buzz" instead of the number
      * If the number is a multiple of 3 AND 5, print "FizzBuzz" instead of the number
*/

func FizzBuzz() {
    func applyLabel(number: Int) -> String {
        switch (number % 3, number % 5) {
        case (0, 0):
            // number divides by both 3 and 5
            return "FizzBuzz!"
        case (0, _):
            // number divides by 3
            return "Fizz!"
        case (_, 0):
            // number divides by 5
            return "Buzz!"
        case (_, _):
            // number does not divide by either 3 or 5
            return "\(number)"
        }
    }
    for value in 1...100 {
        println(applyLabel(value))
    }
}

FizzBuzz()

Swift Exercises.md

Swift Exercises

This is a collection of familiarization exercises in Swift. They'll suffer from ignorance of writing idiomatic code. My goal is to iterate on these as fluency develops and leave them up for the brave.

In short:

• Caveat Lector
• Don't Be A Jerk

Yours Truly,

Erik Hollembeak

^ this looks way too close to C to keep a clear conscience ^

Now here's what I was talking about:

PATTERN MATCHING

func fizzBuzz(number: Int) -> String {
    switch (number % 3, number % 5) {
    case (0, 0):
        // number divides by both 3 and 5
        return "FizzBuzz!"
    case (0, _):
        // number divides by 3
        return "Fizz!"
    case (_, 0):
        // number divides by 5
        return "Buzz!"
    case (_, _):
        // number does not divide by either 3 or 5
        return "\(number)"
    }
}

This feels more in keeping with the language as I've observed it so far

// Is that ok?
func number(){
for i in 1...100{
if i % 3 == 0 && i % 5 == 0{
print("Divided by both 3 & 5")
continue
}
else if i % 3 == 0{
print("Divided by 3")
continue
}
else if i % 5 == 0{
print("Divided by 5")
continue
}

    print(i)
}}

number()