Get the most frequent number from a list.

frequent_number.py

def MostPopularNumber(array, array_length=None):
    """
    Get the most frequent number from an array.
    
    If there arre two or more numbers that appear
    the same number of times, return the lowest.
    
    Parameters
    ----------
    
    array: list
        Array of numbers
        
    array_length: int (deprecated)
        size of array
        
    Returns
    -------
    
    Most frequent number.
    """
    from collections import Counter
    
    # Check if all number of the lista re less than 5000
    for i in array:
        if i <1 or i>5000:
            raise ValueError('Numbers should be between 1 and 5000')
    
    c = Counter(array)

    hi_freq = c.most_common()[0][1]

    most_common = [number 
                   for number, count in c.most_common()
                   if count == hi_freq]

    return min(most_common)

assert MostPopularNumber([34,31,34,77,82], 5) == 34
assert MostPopularNumber([22, 101, 102, 101, 102, 525, 88], 7) == 101
assert MostPopularNumber([66], 1) == 66
assert MostPopularNumber([14, 14, 2342, 2342, 2342], 5) == 2342